I have a string with 14 characters . This is a hex represantation of 7bytes. I want to convert it to binary.
int32_t Hex2Bin( uint8_t * pHexString, uint8_t * pBinArray ){ int o = 0; int i = 0; while ( pHexString[ i ] != 0x00 ) { switch ( pHexString[ i ] ) { case '0': pBinArray[ o ] = 0x00; break; case '1': pBinArray[ o ] = 0x10; break; case '2': pBinArray[ o ] = 0x20; break; case '3': pBinArray[ o ] = 0x30; break; case '4': pBinArray[ o ] = 0x40; break; case '5': pBinArray[ o ] = 0x50; break; case '6': pBinArray[ o ] = 0x60; break; case '7': pBinArray[ o ] = 0x70; break; case '8': pBinArray[ o ] = 0x80; break; case '9': pBinArray[ o ] = 0x90; break; case 'A': case 'a': pBinArray[ o ] = 0xa0; break; case 'B': case 'b': pBinArray[ o ] = 0xb0; break; case 'C': case 'c': pBinArray[ o ] = 0xc0; break; case 'D': case 'd': pBinArray[ o ] = 0xd0; break; case 'E': case 'e': pBinArray[ o ] = 0xe0; break; case 'F': case 'f': pBinArray[ o ] = 0xf0; break; default: return -1; } if ( pHexString[ i + 1 ] == 0x00 ) return -1; switch ( pHexString[ i + 1 ] ) { case '0': pBinArray[ o ] |= 0x00; break; case '1': pBinArray[ o ] |= 0x01; break; case '2': pBinArray[ o ] |= 0x02; break; case '3': pBinArray[ o ] |= 0x03; break; case '4': pBinArray[ o ] |= 0x04; break; case '5': pBinArray[ o ] |= 0x05; break; case '6': pBinArray[ o ] |= 0x06; break; case '7': pBinArray[ o ] |= 0x07; break; case '8': pBinArray[ o ] |= 0x08; break; case '9': pBinArray[ o ] |= 0x09; break; case 'A': case 'a': pBinArray[ o ] |= 0x0a; break; case 'B': case 'b': pBinArray[ o ] |= 0x0b; break; case 'C': case 'c': pBinArray[ o ] |= 0x0c; break; case 'D': case 'd': pBinArray[ o ] |= 0x0d; break; case 'E': case 'e': pBinArray[ o ] |= 0x0e; break; case 'F': case 'f': pBinArray[ o ] |= 0x0f; break; default: return -1; } i += 2; o++; } return o;}